Respuesta :

Answer: 9

Step-by-step explanation:

First solve the system (using elimination):

x-y=7...(1)

3x+2y=26...(2)

Multiply equation 1 by -3

 -3x+3y=-21

+ 3x+2y=26

 -----------------

     5y=5

      y=1

Substitute y=1 into equation 1

x-y=7

x-(1)=7

x=8

Let a=8 (x=a) and y=1 (y=b)

a + b

= (8) + (1)

= 9

Information provided with us :

  • x is assumed as a
  • y is assumed as b

What we have to calculate :

  • Value of a + b ?

Performing Calculations :

Here we have been given with two equations,

  • x - y = 7 (First equation)
  • 3x + 2y = 26 (Second equation)

From the first equation we would be getting a value of x and that value of x we would substitute in the second equation.

x - y = 7

x = 7 + y

Now, substituting it in the second equation :

3x + 2y = 26

3 (7 + y) + 2y = 26

3 × (7 + y) + 2y = 26

21 + 3y + 2y = 26

21 + 5y = 26

5y = 26 - 21

5y = 5

y = 5 / 5

y = 1

Therefore, value of y is 1.

Now, substituting this value of y as 1 in the first equation.

x - y = 7

x - 1 = 7

x = 7 + 1

x = 8

Therefore, value of x is 8.

Value of a + b :-

x = a = 8

y = b = 1

Now,

a + b

8 + 1

9

Henceforth, value of a + b is 9.