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A rock is thrown upward with an initial velocity of 16ft/sec from an initial height 5ft. How much time does it take for the rock to hit the ground?

A. -0.25sec
B. 0.5sec
C. 1.25sec
D. 1.5sec


Answer: C

Respuesta :

Lanuel

The amount of time it would take for the rock to hit the ground is 1.25 seconds.

Given the following data:

  • Initial velocity = 16 ft/sec
  • Height = 5 ft.

Scientific data:

  • Acceleration due to gravity (g) = 9.8 [tex]m/s^2[/tex]

To determine the amount of time it would take for the rock to hit the ground, we would apply the parabolic function:

How to calculate the time.

Mathematically, the parabolic function is given by this formula:

[tex]h(t) = -16t^2 +ut+h_0[/tex]

Where:

  • U is the initial velocity.
  • a is the acceleration.
  • [tex]h_0[/tex] is the height.
  • t is the time.

Substituting the given parameters into the formula, we have;

[tex]0 = -16t^2 +16t+5\\\\16t^2-16t-5=0\\\\(4t+1)(4t-5)=0[/tex]

Taking the positive value of t, we have:

[tex]4t-5-0\\\\4t=5\\\\t=\frac{5}{4}[/tex]

t = 1.25 seconds.

Read more on time here: brainly.com/question/24728358

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