Richard tosses a football with an initial velocity of 10ft/sec from an initial height of 6ft. What is the maximum height the ball will reach?


A. About 7.6ft
B. About 0.3ft
C. 1ft
D. 6ft


Answer: A

Respuesta :

The maximum height the ball will reach is 7.6 ft.

Maximum height of the projectile

The maximum height attained by the projectile is calculated as follows;

v² = u² - 2gh

where;

  • v is the final velocity at maximum height = 0
  • u is the initial velocity
  • h is the height
  • g is acceleration due to gravity

0 = u² - 2gh

2gh = u²

[tex]h = \frac{u^2}{2g} \\\\h = \frac{10^2}{2(32.2)} \\\\h = 1.6 \ ft[/tex]

Thus, the maximum height the ball will reach = 1.6 ft + 6ft = 7.6 ft.

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