Using the percentage concept, it is found that the percentage of 6- to 11-year-olds who were obese was about 17.76% more than the percentage of two- to five-year-olds who were obese.
The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:
[tex]P = \frac{a}{b} \times 100\%[/tex]
Researching on the internet, we find that:
Hence:
[tex]P = \frac{17.9}{15.2} \times 100\% = 117.76\%[/tex]
117.76% - 100% = 17.76%.
Hence the percentage of 6- to 11-year-olds who were obese was about 17.76% more than the percentage of two- to five-year-olds who were obese.
More can be learned about percentages at https://brainly.com/question/24372153