Using it's concept, it is found that the probabilities are:
a. 0.7143 = 71.43% probability that is contains coffee or candy.
b. 0.4348 = 43.48% probability that it contains tea, given that it contain mugs.
c. 0.1558 = 15.58% probability it contains tea and cookies.
A probability is given by the number of desired outcomes divided by the number of total outcomes.
Item a:
There is a total of 20 + 13 + 10 + 12 + 10 + 12 = 77 baskets, of which 20 + 13 + 10 + 12 = 55 contain coffee or candy, hence:
[tex]p = \frac{55}{77} = 0.7143[/tex]
0.7143 = 71.43% probability that is contains coffee or candy.
Item b:
13 + 10 = 23 contain mugs, of which 10 contain tea, hence:
[tex]p = \frac{10}{23} = 0.4348[/tex]
0.4348 = 43.48% probability that it contains tea, given that it contain mugs.
Item c:
Out of the 77, 12 contain tea and cookies, hence:
[tex]p = \frac{12}{77} = 0.1558[/tex]
0.1558 = 15.58% probability it contains tea and cookies.
More can be learned about probabilities at https://brainly.com/question/15536019
