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100 points!!!
“The revenue equation for a certain brand of toothpaste is y=2.6x, where X is the number of toothpaste sold and y is the income for selling X tubes. Cost equation is y=X+2000, where X is the number of tubes of toothpaste manufactured and y is the cost of producing X tubes. The following set of axis shows the graph of the cost and revenue equations. For what X-values will the company make a profit”

The company will make a profit for X-values: (greater than, less than, or equal to) ____?

100 points The revenue equation for a certain brand of toothpaste is y26x where X is the number of toothpaste sold and y is the income for selling X tubes Cost class=

Respuesta :

Answer:

The revenue equation  is y=2.6x,

cost equation is y=x+2000

When the company makes profit only when  revenue > cost

Lets frame inequality using revenue > cost

Replace the revenue equation and cost equation

Now solve the inequality for x

Subtract 1x from both sides

Divide both sides by 1.6

The company makes profit when x is greater than 1250

Step-by-step explanation:

RevyBreeze

Answer:

Greater than 1250

x > 1250

Step-by-step explanation:

Base on  the revenue equation and cost equation , we can infer that the company make a profit when x > 1250

Important Given Information:

The revenue equation  is [tex]y=2.6x[/tex]

Cost equation is [tex]y = x+2000[/tex]

When the company makes profit only when: [tex]revenue > cost[/tex]

Let's frame inequality using: [tex]revenue > cost[/tex]

Replace the revenue equation and cost equation

[tex]Revenue > Cost: 2.6x > + 2000[/tex]

Now Let's solve the inequality for x

[tex]2.6x > 1x + 2000[/tex]

[tex]2.6x - 1x > 2000[/tex]        [tex][2.6x-1x=1.6x][/tex]

[tex]1.6x > 2000[/tex]

Divide both sides by 1.6 ( what you do on one side do to the other)

[tex]\frac{1.6x}{1.6}=\frac{2000}{1.6}[/tex]

[tex]x >1250[/tex]

Hence, the company makes profit when x is greater than 1250

[RevyBreeze]

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