A manufacturing corporation make tires with a probability 0.79 of lasting over 3,000 miles. What is the probability of exactly seven out of the next eight tires lasting over 3,000 miles?
(Round your answer to three decimal places.)

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Answer:

A manufacturing corporation make tires with a probability 0.77 of lasting over 3,000 miles.

Step-by-step explanation:

The probability of exactly seven out of the next eight tires lasting over 3,000 miles will be 0.32.

How to find that a given condition can be modelled by binomial distribution?

Binomial distributions consist of n independent Bernoulli trials.

Bernoulli's trials are those trials which end up randomly either on success (with probability p) or on failures (with probability 1- p = q (say))

The probability that out of n trials, there'd be x successes is given by

[tex]\rm P(X =x) = \: ^nC_x \ p^x(1-p)^{n-x}[/tex]

A manufacturing corporation make tires with a probability 0.79 of lasting over 3,000 miles.

The probability of exactly seven out of the next eight tires lasting over 3,000 miles will be

P(x = 7) = ⁸C₇ (0.79)⁷  (1 – 0.79)⁽⁸⁻⁷⁾

P(x = 7) = 0.32

Learn more about binomial distribution here:

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