Answer:
vertex = (6, -9)
point = (0, 27)
see attached diagram for graph
Step-by-step explanation:
[tex]f(x)=x^2-12x+27[/tex]
Vertex form: [tex]y=a(x-h)^2+k[/tex]
where (h, k) is the vertex
Rewrite function in vertex form:
[tex]\implies f(x)=(x-6)^2-36+27[/tex]
[tex]\implies f(x)=(x-6)^2-9[/tex]
Therefore, vertex = (6, -9)
As the coefficient of [tex]x^2[/tex] is positive, the parabola will open upwards (u shaped).
Point to plot:
f(0) = 27
Therefore, point = (0, 27)
