Find the area of each shaded region

[tex]\bold{\huge{\blue{\underline{ Solution }}}}[/tex]
The given figure is composed of two figures triangle and circle. In which triangle is enclosed in the circle.
We know that,
Area of triangle
[tex]\bold{\red{ = }}{\bold{\red{\dfrac{1}{2}}}}{\bold{\red{\times{ Base }}}}{\bold{\red{\times{ height }}}}[/tex]
Here,
Subsitute the required values,
Area of the given triangle
[tex]\sf{ = }{\sf{\dfrac{1}{2}}}{\sf{\times{ 10 }}}{\sf{\times{ 5 }}}[/tex]
[tex]\sf{ = 5 }{\sf{\times{ 5}}}[/tex]
[tex]\bold{ = 25\: units }[/tex]
Thus, The area of triangle is 25 units
We have to find the area of the circle
We know that,
Area of circle
[tex]\bold{\pink{ = }}{\bold{\pink{\pi{r^{2}}}}}[/tex]
Subsitute the required values,
[tex]\sf{ = }{\sf{\pi{(5)^{2}}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{22}{7}}}{\sf{\times{ 25}}}[/tex]
[tex]\sf{ = }{\sf{\dfrac{550}{7}}}[/tex]
[tex]\bold{ = 78.57\: units }[/tex]
Thus, The area of circle is 78.57 units
Area of shaded region
= Area of circle - Area of triangle
Subsitute the required values,
[tex]\sf{ = 78.57 - 25 }[/tex]
[tex]\bold{\green { = 53.57 \: units }}[/tex]
Hence, The area of shaded region is 53.57 units.
The area of the shaded figure is 13.375 square units.
The shaded region is a circle with a triangle inside of it removed.
To get the area, we need to get the area of the circle and remove the area of the triangle.
Remember that for a circle of radius R, the area:
A = 3.14*R^2
In this case, we can see that the diameter of the circle measures 5 units, then the radius (half of the diameter) measures 2.5 units.
A = 3.14*(2.5)^2 = 19.625 square units.
And a triangle of base B and height H has an area:
A' = B*H/2
In this case, the base of the triangle is equal to the diameter of the circle, and the height is equal to the radius of the circle, so we have:
B = 5 units.
H = 2.5 units.
Then:
A' =5*2.5/2 = 6.25 square units.
Then the shaded area is:
shaded area = 19.625 square units - 6.25 square units.
= 13.375 square units.
If you want to learn more about areas, you can read:
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