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Find three consecutive odd integers such that three times the greatest is 7 less than the
sum of the smallest and middle integer.

Respuesta :

Consecutive odd integers are odd integers that have a difference of 2

The consecutive integers are -17, -15 and -13

How to determine the integers

Let the integers be x, y and z (from least to greatest)

So, we have:

[tex]3z =x + y - 7[/tex]

Also, we have:

[tex]y = x + 2[/tex]

[tex]z = x + 4[/tex]

So, we have:

[tex]3z =x + y - 7[/tex]

[tex]3(x + 4) = x + x + 2 - 7[/tex]

Open the bracket

[tex]3x + 12 = x + x + 2 - 7[/tex]

Collect like terms

[tex]3x -x -x = 2 - 7-12[/tex]

[tex]x = -17[/tex]

Hence, the consecutive integers are -17, -15 and -13

Read more about consecutive numbers at:

https://brainly.com/question/10853762