stohmz
contestada

23/02/2022 QUESTION ONE A coil of inductance 318.3mH and negligible resistance is connected in series with a 200 resistor to a 240V, 50 Hz supply. Calculate: a) The inductive reactance of the coil, (b) The impedance of the circuit, 512 (c) The current in the circuit, (d) The p.d. across each component, and (e) The circuit phase angle.​

Respuesta :

pstnonsonjoku

The impedance of the circuit is 200 ohm.

What is reactance?

The term reactance refers to the opposition offered to the flow of current by the inductor or capacitor.

a) The inductive reactance is given by;

XL = 2πFL = 2 × (3.14) × 50 × 318.3 × 10^-3 = 100 ohm

b) Z = √R^2 + XL^2

Z = √(200)^2 + (100)^2

Z = 223.6 ohm

c) I = V/Z = 240V/223.6 ohm = 1.1 A

d) P.d across the resistor; IR = 1.1 A × 200 ohm = 220 V

P.d across inductor = IXL = 1.1 A ×  100 ohm = 110 V

e) Phase angle = tan^-1 (X/R) = tan^-1 (100/200) = 27 degrees.

Learn more about impedance:https://brainly.com/question/2263607

Otras preguntas