Respuesta :

mhanifa

Answer:

  • B) 20, E) 6C3

Step-by-step explanation:

Combination of 3 juniors out of 6 is:

  • 6C3 = 6!/(6 - 3)!3! = 6*5*4*3!/3!3! = 6*5*4/2*3 = 5*4 = 20

Correct choices are B and E

We shall use combination here

  • n=6
  • r=3

[tex]\boxed{\sf ^nC_r=\dfrac{n!}{r!(n-r)!}}[/tex]

Now

[tex]\\ \rm\Rrightarrow ^6C_3[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{6!}{3!(6-3)!}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{720}{3!(6)}[/tex]

[tex]\\ \rm\Rrightarrow 20[/tex]

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