Digram:
[tex]\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 9\ cm}\end{picture}[/tex]
Given :
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- Radius of circle = 9cm
- π = 314
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To find:
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Solution:
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We know:-
[tex] \bigstar \boxed{ \rm Area \: of \: circle = \pi {r}^{2} }[/tex]
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So:-
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[tex] \dashrightarrow\sf Area \: of \: circle = 314 \times {9}^{2}[/tex]
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[tex] \dashrightarrow\sf Area \: of \: circle = 314 \times 9 \times 9 \\ [/tex]
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[tex] \dashrightarrow\sf Area \: of \: circle = 314 \times 81 \\ [/tex]
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[tex] \dashrightarrow\bf Area \: of \: circle = 25434 \: unit^2\\ [/tex]
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.°. Option D is correct
