Ⲁⲛ⳽ⲱⲉⲅ:
- Diameter = 2 mm ( approx )
[tex] \quad{\rule{300pt}{1.5pt}}\quad[/tex]
Ⲋⲟⳑⳙⲧⳕⲟⲛ :
We are given that :
- The circumference of a circle is 6.28mm
We know that :
[tex]\qquad\bull{\boxed {\mathfrak{Circumference = 2 \pi r }}}\bull[/tex]
Therefore,
[tex] \quad\dashrightarrow\quad \sf { 6.28 = 2 \pi r }[/tex]
[tex] \quad\dashrightarrow\quad \sf {r = \dfrac{6.28}{2\pi} }[/tex]
[tex] \quad\dashrightarrow\quad \sf {r = \dfrac{6.28\times 7}{22\times 2} }[/tex]
[tex] \quad\dashrightarrow\quad \sf {r =\cancel{\dfrac{43.64}{44}} }[/tex]
[tex] \quad\dashrightarrow\quad \sf {r = 0.9989 }[/tex]
As we know,
[tex] \quad\dashrightarrow\quad \sf { Diameter = 2\times radius}[/tex]
[tex] \quad\dashrightarrow\quad \sf { Diameter = 2\times 0.9989}[/tex]
[tex] \quad\dashrightarrow\quad \sf { Diameter = 1.98 }[/tex]
[tex] \quad\dashrightarrow\quad {\pmb{\sf {Diameter = 2 mm ( approx ) }}}[/tex]
[tex] \rule{300pt}{2pt}[/tex]
