The extraneous solution of the logarithmic problem [tex]\rm log_3(18x^3)-log_3(2x) = log_3 144[/tex] is -4.
A log function is a way to find how much a number must be raised in order to get the desired number.
[tex]a^c =b[/tex]
can be written as
[tex]\rm{log_ab=c[/tex]
where a is the base to which the power is to be raised,
b is the desired number that we want when power is to be raised,
c is the power that must be raised to a to get b.
Solving the function using the basic logarithmic value, we get,
[tex]\rm log_3(18x^3)-log_3(2x) = log_3 144\\\\ log_3\dfrac{(18x^3)}{(2x)} = log_3 144\\\\ log_3(9x^2)= log_3 144\\\\\text{Taking antilog}\\9x^2 = 144\\x = \sqrt{\dfrac{144}{9}}[/tex]
If we solve further we will get that the value of x can be either -4 or 4, if take the value of x as -4, in the beginning then you will get log₃(18(-4)³) as the log of negative value which is impossible.
Hence, x=-4 is an extraneous solution.
Learn more about Logarithms:
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