The equilibrium constant of the second reaction is 0.155.
The equilibrium constant is a numerical value that shows the extent to which reactants are converted into products at a given temperature.
Now, we have the reaction; 3Z + Q ⇄ 2 X and 4 X ⇄ 6 Z + 2 Q.
In the first reaction;
K =[ X]^2/[Z]^3 Q
In the second reaction;
[Z]^6 [Q]^2/[X]^4
Let [ X]^2 = A
[Z]^3 Q = B
Then the second reaction can be;
K = (B)^2/(A)^2 = (B/A)^2
The equilibrium constant of the second reaction therefore is; (1/2.54)^2
K = 0.155
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