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what is the new tempature of a aluminium baking sheet with mass of 225 grams absorbs 2.4 times 10 to the 4 joules if its tempature was 25 celsius

Respuesta :

Eduard22sly

The new temperature of the aluminium baking sheet is 144.85 °C

Data obtained from the question

  • Mass of nitrogen (M) = 225 g
  • Heat (Q) = 2.4×10⁴ J
  • Initial temperature (T₁) = 25 °C
  • Specific heat capacity (C) = 0.89 J/gºC
  • Final temperature (T₂) =?

How to determine the new temperature

The new (i.e final) temperature of the aluminium sheet can be obtained as follow:

Q = MC(T₂ – T₁)

2.4×10⁴ = 225 × 0.89 × (T₂ – 25)

2.4×10⁴ = 200.25 × (T₂ – 25)

Divide both side by 200.25

2.4×10⁴ / 200.25 = (T₂ – 25)

119.85 = T₂ – 25

Collect like terms

T₂ = 119.85 + 25

T₂ = 144.85 °C

Learn more about heat transfer:

https://brainly.com/question/10286596

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