Answer:
[tex] \underline{1}Zn +\underline{ 2}HCL\to \underline{1}ZnCl_2+\underline{1}H_2 [/tex]
Explanation:
Here we need to balance the given reaction. The reaction is ,
[tex] \underline{\quad} Zn +\underline{\quad}HCl \to \underline{\quad}ZnCl_2+\underline{\quad}H_2[/tex]
Firstly let's make a table here to see the number of elements in LHS and RHS as ,
[tex] \boxed{\begin{tabular}{c|c} LHS & RHS \\\\\cline{1-2}\\\\ Zn = 1 & Zn = 1 \\\\ H =1$\times$2=2& H = 2 \\\\ Cl =1$\times$2=2 & H =2\end{tabular}} [/tex]
- We just need to multiply 2 to HCl on LHS in order to balance the equation. Therefore,
Our final reaction is,
[tex] \underline{1}Zn +\underline{ 2}HCL\to \underline{1}ZnCl_2+\underline{1}H_2 [/tex]
This is our required answer!
