Answer:
[tex]x = 1.5[/tex] , [tex]x = 1[/tex]
Explanation:
[tex]x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
equation:
- 2x² - 5x + 3 = 0 ..........turned into this form: ax² + bx + c = 0
Here the a = 2 , b = -5 , c = 3
using the equation:
[tex]\hookrightarrow x = \dfrac{ -(-5) \pm \sqrt{(-5)^2 - 4(2)(3)}}{2(2)}[/tex]
[tex]\hookrightarrow x = \dfrac{ 5 \pm \sqrt{1}}{4}[/tex]
[tex]\hookrightarrow x = \dfrac{ 5 +\sqrt{1}}{4}[/tex] , [tex]x = \dfrac{ 5 -\sqrt{1}}{4}[/tex]
[tex]\hookrightarrow x = \dfrac{ 5 +1}{4}[/tex] , [tex]x = \dfrac{ 5 -1}{4}[/tex]
[tex]\hookrightarrow x = \dfrac{ 6}{4}[/tex] , [tex]x = \dfrac{ 4}{4}[/tex]
[tex]\hookrightarrow x = 1.5[/tex] , [tex]x = 1[/tex]
