This problem is providing us with the moles of both sugar and ammonia and asks for a comparison between the moles and their amounts in grams. At the end, one concludes they have different amounts as 1,743.42 g and 119.21 g.
Mole-mass relationships
In chemistry, mole-mass relationships are used to calculate grams from moles or vice versa, according to specific conditions. In such a way, for sugar and ammonia, one can first calculate their molar masses with:
[tex]MM_{C_6H_{12}O_{11}}=6*12.01+12*1.01+11*16.00=249.06g/mol\\ \\MM_{NH_3}=14.01+1.01*3=17.03g/mol[/tex]
Next, we calculate grams with the following proportional factors:
[tex]7molC_6H_{12}O_{11}*\frac{249.06gC_6H_{12}O_{11}}{1molC_6H_{12}O_{11}} =1743.42g\\\\7molNH_3*\frac{17.03gNH_3}{1molNH_3}=119.21gNH_3[/tex]
Thus, we conclude that despite having equal number of moles, they differ in the amount of grams because of their dissimilar molar masses.
Learn more about mass and moles: https://brainly.com/question/26727229
