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If 1 mole of a gas is equal to 22.4 L at standard temperature and pressure (STP), how many liters is occupied by 16.3 moles of oxygen gas at STP?

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If 1 mole of a gas is equal to 224 L at standard temperature and pressure STP how many liters is occupied by 163 moles of oxygen gas at STP Use this if you can class=

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If 1 mole of a gas is equal to 22.4 L at standard temperature and pressure (STP), 365.34 liters is occupied by 16.3 moles of oxygen gas at STP.

HOW TO CALCULATE VOLUME?

The volume of a given gas can be calculated as follows:

PV = nRT

Where;

  1. P = pressure (atm)
  2. V = volume (L)
  3. n = number of moles
  4. T = temperature (K)
  5. R = gas law constant

V = nRT/P

V = 16.3 × 0.0821 × 273 ÷ 1

V = 365.34 liters

Therefore, If 1 mole of a gas is equal to 22.4 L at standard temperature and pressure (STP), 365.34 liters is occupied by 16.3 moles of oxygen gas at STP.

Learn more about volume at: https://brainly.com/question/1578538

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