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VirαtKσhli

Given :-

  • mass of car = 975 kg .
  • Initial velocity = 0m/s
  • Final velocity = 26.7 m/s
  • Distance = 120 m

To Find :-

  • The magnitude of average net force acting on the car.

Solution :-

Firstly let's find out the acceleration as ,

→ 2as = v² - u²

→ 2*a*120m = (26 m/s)² -0²

→ a = 26m/s *26m/s ÷(240m)

→ a = 2.81 m/s²

Again , we know that ,

→ F = mass * acceleration

→ F = 975kg * 2.81m/s²

→ F = 2739.75 N

Hence the required answer is 2739.75 N .

okpalawalter8

The magnitude of the average net force on the car is mathematically given as

F=5791.5N

What is the magnitude of the average net force acting on the car?

Question Parameter(s):

A 975-kg car accelerates from rest to 26. 7 m/s in a distance of 120 m.

Generally, the equation for the Force   is mathematically given as

F=m*a

Where

t=d/vt

t=120/26.7

t=4.49sec

a=v/t

a= 26. 7/4.49

a=5.94m/s^2

In conclusion

F=m*a

F=975-kg*5.94m/s^2

F=5791.5N

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