Answer:
IJ = 13
Step-by-step explanation:
If two secant segments are drawn to a circle from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
Given:
- Secants: IJK and MLK
- Point of intersection: K
So JK · IJK = LK · MLK
If MK = 15 and ML = 9, then LK = 15 - 9 = 6
Given JK = 5
⇒ JK · IJK = LK · MLK
⇒ 5 · IJK = 6 · 15
⇒ 5 · IJK = 90
⇒ IJK = 90 ÷ 5 = 18
IJ = IJK - JK
⇒ IJ = 18 - 5 = 13
