Respuesta :

chetankachana

Answer:

m∠UQT = 52°
m∠UTQ = 42°
x = 1

Step-by-step explanation:

∠UQT is an alternate interior angle of ∠RSQ

Therefore, ∠UQT is 52°

∠UTQ is an alternate interior angle of ∠URS

Therefore, ∠UTQ is 42°

The diagonals of a parallelogram are congruent, so 4x + 1 is 5

  • 4x + 1 = 5
  • 4x = 4
  • x = 1

-Chetan K
  • QR||TS

QS is the intersector

  • <UQT=<QSR(Alternative interior angles)=52°

Similarly

  • <UTQ=<URS=42°

Now

Diagonals of parallelogram bisect eachother

[tex]\\ \rm\Rrightarrow 4x+1=5[/tex]

[tex]\\ \rm\Rrightarrow 4x=4[/tex]

[tex]\\ \rm\Rrightarrow x=1[/tex]

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