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The potential difference between the two plates of a capacitor is 8. 5 v. If the separation between the plates is 4. 1 mm, what is the strength of the electric field between the plates n/c?.

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leena

Hello!

We can use the following equation:

[tex]V = Ed[/tex]

V = Potential Difference (V)

E = Electric Field (N/C)

d = distance between plates (m)

Begin by converting 4.1 mm to m.

1 mm = 0.001 m

4.1 mm = 0.0041 m

Now, we can solve for the electric field strength.

[tex]E = \frac{V}{d} = \frac{8.5}{0.0041} = \boxed{2037.17 \frac{N}{C}}[/tex]

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