Respuesta :
The measure of line segment BC is; 10cm
The angle measure m∠bcd is; 120°
The measure of line segment AB is; 5 cm
The measure of line segment BE is; 4.33 cm
Line segments and angle measures in a parallelogram
By convention, for parallelograms, the length of its opposite sides are equal, it follows that;
- AB = CD = 5cm and
- AD = BC
Additionally, the measure of the adjacent angles is supplementary;
m∠C + m∠D = 180
On this note, it follows that, m<BCD = 120°, since m∠D is; 60° from the diagram
From the sine rule of triangle sides and angles; the measure of line segment BE can be evaluated as follows;
- BD/sin 120 = CD/sin 30
- BD/sin120 = 2(5)
- BD = 10sin120
BD = 8.66
Hence, since BD = 2BE holds from the diagram;
- BE = BD/2
- BE = 8.66/2
BE = 4.3
The image attached is the complete question.
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