By splitting the middle term we get solution of quadratic equation as 12 and -2
Any equation that can be rearranged in standard form as
[tex]ax^{2}+bx+c=0,[/tex]
where a is not zero is called quadratic equation.
Given equation
[tex]a^{2}-10 a+25=49\\\\\\a^{2}-10 a+25-49=0\\\\\\a^{2}-10 a-24=0\\[/tex]
Now we can split middle term
[tex]a^{2}-12a+2a-24=0\\[/tex]
Now factorization
[tex](a-12)(a+2)=0[/tex]
[tex]\\ $a_{1}=12$ \ \ \\\\ $a_{2}=-2$.[/tex]
By splitting the middle term we get solution of quadratic equation as 12 and -2
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