100 POINTS!!! //
Which table contains a set of non-linear ordered pairs?

x y
0 1
1 2
2 3
3 4

x y
0 4
1 7
2 10
3 13

x y
0 1
1 2
2 5
3 10

x y
0 7
1 5
2 3
3 1

To answer this question we have to recall what is the meaning of a linear ordered pair. As you can see, in every table there are 4 values for x, and 4 values for y. In every case, the set of values for x are

x=\{0, 1, 2, 3\}x={0,1,2,3}

but in every table, the values for y varies. Now, the key is to calculate the variation of these values, and in order to have a linear relation between x and y, the variation must be the same quantity for every y value that depend of each x value.

For example, in table B, the variation is +3, as from the first y value to the second, 3 is added... and this +3 variation must be the same for each new value of y (and as you can see, 4+3 is 7, 7+3 is 10, 10+3 is 13).

Keeping this in mind, the variation in table C is -2, and the variation in table D is +1, so tables B, C and D contains sets of linear ordered pairs.

To answer the question, we just have to realise that table A has differents variations in the values of y, and this means that it contains a set ofnon-linear ordered pairs, wi

h is the correct answer to the question

100 POINTS!!! // Which table contains a set of non-linear ordered pairs? x y 0 1 1 2 2 3 3 4 x y 0 4 1 7 2 10 3 13 x y 0 1 1 2 2 5 3 10 x y 0 7 1 5 2 3 3 1

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100 POINTS!!! //
Which table contains a set of non-linear ordered pairs?

x y
0 1
1 2
2 3
3 4

x y
0 4
1 7
2 10
3 13

x y
0 1
1 2
2 5
3 10

x y
0 7
1 5
2 3
3 1