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Solve question no. 2 or 3 .

Questions refer to the above attachment.

Note :
Need Genuine Answer..​
Kindly don't copy from other web

Need Help Solve question no 2 or 3 Questions refer to the above attachmentNote Need Genuine AnswerKindly dont copy from other web class=

Respuesta :

mhanifa

Answer:

  • See below

Step-by-step explanation:

Q2

Tangents from same point have same length.

APB is isosceles triangle:

  • m∠PAB = 1/2(180 - m∠APB) = 90 - 1/2m∠APB

We have AP ⊥ AO, so:

  • m∠OAB = 90 - m∠PAB = 90 - (90 - 1/2m∠PAB) =  1/2m∠APB
  • m∠APB = 2m∠OAB

Correct choice is D

Q3

Let A and B are the points on the circle, the tangents are PA and PB.

OAP and OBP are right angles.

OP is the hypotenuse of right triangles OAP and OBP.

One of the legs is half the length of the hypotenuse since OA = r and OP = 2r.

It means the angle opposite to radius is 30° according to the property of 30°×60°×90° triangle:

  • m∠APO = m∠BPO = 30°

The angle between two tangents is:

  • m∠APB = 2m∠APO = 2*30° = 60°

Correct choice is C

Parrain

Based on the tangents, we can find that ∠APB is equal to D. ∠OAB.

When a pair of tangents is drawn to a circle with centre O and radius from P, the angle between the two tangents is 60°.

What is ∠APB equal to?

Based on the fact that APB is an isoceles triangle, we can have a situation where:

m∠OAB = 90

- m∠PAB = 90 - (90 - 1/2m∠PAB) =  1/2m∠APB

This leaves us with:

m∠APB = 2m∠OAB

What is the angle between the two tangents?

With OAP and OBP being right angles, we find that:

m∠APO = m∠BPO = 30°

The angle between the two tangents cab therefore be found to be:

=  2m∠APO

= 2 x 30°

= 60°

Find out more on tangents at https://brainly.com/question/1539108.

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