Answer:
A student is pushing a = 35 kg desk across a floor at a constant speed of 1 = 4 m/s. How
much work, to the nearest whole joule, must the student do on the desk to change the speed to
2 = 6 m/s?
Solution:
Work done = change of energy
=
2
2
2
−
1
2
2
=
35 × 36
2
−
35 × 16
2
= 630 − 280 = 350 J
Answer = 350 J
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