The motion of the baseballs under gravity are given by kinematic
equations of motion.
Response:
The height functions are;
[tex]1) \hspace{0.15 cm} h = 121 - \frac{1}{2} \times 9.81 \times t^2[/tex]
[tex]2) \hspace{0.15 cm} h = 225 - \frac{1}{2} \times 9.81 \times t^2[/tex]
According to the kinematic equations of motion, we have;
h = u·t + [tex]\mathbf{\frac{1}{2}}[/tex]·g·t²
Where;
h = The height from which the ball is dropped
u = The initial velocity of each baseball = 0
g = Acceleration due to gravity ≈ 9.81 m/s²
t = The time taken
Which gives the following height functions
[tex]1) \hspace{0.15 cm} \underline{h = 121 - \frac{1}{2} \times 9.81 \times t^2}[/tex]
[tex]2) \hspace{0.15 cm} \underline{h = 225 - \frac{1}{2} \times 9.81 \times t^2}[/tex]
By comparison of the graphs of the height functions, we have that the
shapes of both graphs are parabolic.
The y-intercepts are;
The x-intercepts (approximate values) are;
Baseball dropped from 121 feet; x-intercept (4.97, 0)
Baseball dropped from 225 feet; x-intercept (6.77, 0)
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