Answer:
(0, 4)
Step-by-step explanation:
Hi there!
We are given the following systems of equations:
x=8-2y
y-x=4
And we want to solve it by substitution
When we solve an equation by substitution, we solve for one of the variables in one of the expressions, which should be an expression containing the other variable, then we substitute that expression as the variable we solved for into the other expression to find the value of that variable, then use the value of the solved variable to find the value of the other variable.
In this case, we already have x solved in the first equation; x is equal to 8-2y.
We can substitute that as x in y-x=4 to solve for y.
y-(8-2y)=4
Subtract
y-8+2y=4
Combine like terms
3y-8=4
Add 8 to both sides
3y=12
Divide both sides by 3
y=4
Substitute 4 as y into x=8-2y to solve for x.
x=8-2(4)
x=8-8
x=0
The solution is x=0, y=4, or as a point, (0, 4)
Hope this helps!
See more on solving systems of equations by substitution here: https://brainly.com/question/26734132
