If f(–5) = 0, what are all the factors of the function f (x ) = x cubed minus 19 x 30? Use the Remainder Theorem. (x – 2)(x 5)(x – 3) (x 2)(x – 5)(x 3) (x – 2)(x 5) (x 2)(x – 5).

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Answer:

A. (x – 2)(x + 5)(x – 3) on edg

Step-by-step explanation:

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When a polynomial P(x) is divided by (x-t) then the remainder of the division is equal to P(t). If P(t)=0, then the (x-t) is the factor of the polynomial. The factors of x³-5x+6 are (x+5)(x-2)(x-3).

What is the Remainder theorem?

According to the remainder theorem, when a polynomial P(x) is divided by (x-t) then the remainder of the division is equal to P(t). If P(t)=0, then the (x-t) is the factor of the polynomial.

Since f(–5) = 0, therefore, (x+5) is a factor of the polynomial f(x).

[tex]\dfrac{x^3-19x+30}{x+5} = x^2-5x+6[/tex]

Now, x² -5x + 6 can be factorised as,

x² - 5x + 6

x² - 2x - 3x + 6

x(x-2) -3 (x-2)

(x-2)(x-3)

Hence, the factors of x³-5x+6 are (x+5)(x-2)(x-3).

Learn more about the Remainder Theorem:

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