A pitcher supplies a power of P = 216 W to a baseball of mass m = 0.085 kg for a period of t = 0.27 What is the ball's speed in m/s when it leaves his hand?

Respuesta :

The speed of the ball is 37.04 m/s

What is speed?

Speed can be defined as the ratio of the distance to the time of a body.

To calculate the speed of the ball, we use the formula below.

Formula:

  • P = mv²/2t............. Equation 1

Where:

  • P = Power of the pitcher
  • m = mass of the ball
  • v = speed of the ball
  • t = time.

From the question,

Given:

  • m = 0.085 kg
  • P = 216 W
  • t = 0.27 seconds

Substitute these given values into equation 1

  • 216 = 0.085(v²)/(2×0.27)

solve for v

  • 0.085(v²) = 216×2×0.27
  • v² = 216×2×0.27/0.085
  • v² = 1372.24
  • v = √(1372.24
  • v = 37.04 m/s

Hence, The speed of the ball is 37.04 m/s.
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