The depth of the water at the end of a pier changes periodically along with the movement of tides. On a particular day, low tides occur at 12:00 am and 12:30 pm, with a depth of 2. 5 m, while high tides occur at 6:15 am and 6:45 pm, with a depth of 5. 5 m. Let t = 0 be 12:00 am. Graph the equation equationthat models the situation using a graphing calculator and use it to answer the following questions. How many times during this day is the depth at the end of the pier equal to 4 meters? 2 times 3 times 4 times 5 times.

Respuesta :

we get the graph of cosine function.

Here we have given that the low tides occur at a depth of 2.5 m at 12:00 am and 12:30 pm,

separated by the period of T = 12.5 hours. and also high tides occur at a depth of 5.5 m at 6:15 am and 6:45 pm,

separated by a period of T = 12.5 hours.

From the diagram we have use the value of t tor finding the amplitude

So,

What is the formula of amplitude ?

(max+min)/2

Therefore,

The amplitude is,

[tex]\frac{1}{2} (5.5 - 2.5) = 1.5 m.[/tex]

x(0)=2.5 and x(T/2)=5.5

from the diagram  we can say that the function is periodic

[tex]x(t)=-1.5cos(\frac{2\pi t}{12.30} )+4[/tex]

Therefore,

we get the graph of cosine function.

To learn more about pier changes periodically along with moment of tides visit:

https://brainly.com/question/19799703

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Answer:

C. 4 times

Step-by-step explanation:

the next one is B. 4:00 am