The magnitude of the tension in the string is 9.31 N.
The magnitude of the tension in the string in the horizontal circle formed by the turn table is calculated as follows;
T = Fcos(θ)
where;
[tex]T = \frac{mv^2}{r} \times cos(\theta)\\\\T = \frac{3 \times 4.5^2}{5} \times cos(40)\\\\T = 9.31 \ N[/tex]
Thus, the magnitude of the tension in the string is 9.31 N.
The complete question is below:
A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine the magnitude of the tension in the string.
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