Answer:
200 m
Step-by-step explanation:
[tex]v = 60 km/h \times\frac{1000m}{1km}\times\frac{1h}{3600sec}}=\frac{60}{3.6}m/s[/tex]
For the passenger, the other train moves at a rate of 2v
Time t = 6 sec
The length = (2v) x t = [tex]2\times\frac{60}{3.6}\times 6=200 m[/tex]