What is the distance between (5, –1) and (5, –4)?

On a coordinate plane, points are at (5, negative 1) and (5, negative 4).
1 unit
3 units
4 units
5 units

Respuesta :

Answer:

[tex]d=3\ units[/tex]

Step-by-step explanation:

The distance formula is:

[tex]d = \sqrt {\left( {x_2 - x_1 } \right)^2 + \left( {y_2 - y_1 } \right)^2[/tex]

We can plug in the given coordinate pairs into the formula:

[tex]d = \sqrt {\left( {5-5\right)^2 + \left( {4-(-1) } \right)^2[/tex]

[tex]d = \sqrt {\left( {0 } \right)^2 + \left( {-4+1} \right)^2[/tex]

[tex]d=\sqrt{0+(-3)^2}[/tex]

[tex]d=\sqrt{0+9}[/tex]

[tex]d=\sqrt{9}[/tex]

[tex]d=3\ units[/tex]

Answer:

3 or b

Step-by-step explanation:

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