What is the osmotic pressure of a solution of FeCl3(aq) in which 69.5 g of FeCl3(s) (molar mass = 162.20 g mol-1) are dissolved in a solution with a total volume of 2.35 L at 35.0 °C?

Respuesta :

The osmotic pressure of the solution is 25.48atm

Data;

  • Mass = 69.5g
  • Molar mass = 162.20g/mol
  • Volume = 2.35L
  • Temperature = 35.0^oC

Osmotic Pressure

The osmotic pressure of the solution is calculated as

[tex]\pi = iMRT[/tex]

  • i = Vant Hoff Factor
  • M = molarity
  • R = gas constant
  • T = Temperature

The Vant hoff factor of the factor = 4

Let's calculate the molarity of the solution;

[tex]M = \frac{number of moles}{volume}[/tex]

Number of moles = mass / molar mass

[tex]n = \frac{mass}{molar mass} \\[/tex]

substitute the values into the formula and solve for it

[tex]n = \frac{69.5}{162.20} \\n = 0.428 moles[/tex]

The molarity of the solution is calculated as

[tex]M = \frac{number of moles}{volume} \\M = \frac{0.428}{2.35} = 0.182 mol/L[/tex]

The osmotic pressure of the solution is calculated as

[tex]\pi = iMRT\\\pi = 4 * 0.182 * 35\\\pi = 25.48 atm[/tex]

The osmotic pressure of the solution is 25.48atm

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