From a survey of 100 college students, a marketing research company found that 55 students owned iPods, 25 owned cars, and 5 owned both cars and iPods.

How many students do not own either a car or an iPod?

Respuesta :

Answer:

Correct option is B)

n(AUB)=n(A)+n(B)−n(A∩B)

     =75+45−35

=85

number of students owing car or stereos=85

number of students neither car nor stereo =100−85=15

The number of students who do not own either a car or an iPod is 25.

What is union of sets?

Union of two given sets is the smallest set which contains all the elements of both the sets.

What is intersection of sets?

Intersection of two given sets is the largest set which contains all the elements that are common to both the sets

What is the formula for union of two sets?

The union of two sets is given by

n(A∪B) = n(A) + n(B) -n(A∩B)

Where,

A and B are the two sets.

∪ is the union

∩ is the intersection.

According to the given question.

Total number of students in a college = 100

Total number of students who own iPods, n(A) = 55

Total number of students who own cars, n(B) = 25

Number of students who own both cars and iPods, n(A∩B) = 5

Therefore,

The number of students who own cars or iPods is given by

n(A∪B) = n(A) + n(B) - n(A∩B)

⇒n(A∩B) = 55 + 25 - 5

n(A∪B) = 75

So, the number of students who do not own either a car or an iPod

= 100 - 75

= 25

Hence, the number of students who do not own either a car or an iPod is 25.

Find out more information about intersection and union of sets here:

https://brainly.com/question/4709512

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