Answer: D) 12 units
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Explanation:
Point M is at (4,6) and point M' is at (-4, -3) after shifting 8 units left and 9 units down.
Apply the distance formula.
[tex]M = (x_1,y_1) = (4,6) \text{ and } M' = (x_2, y_2) = (-4,-3)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(4-(-4))^2 + (6-(-3))^2}\\\\d = \sqrt{(4+4)^2 + (6+3)^2}\\\\d = \sqrt{(8)^2 + (9)^2}\\\\d = \sqrt{64 + 81}\\\\d = \sqrt{145}\\\\d \approx 12.041595\\\\d \approx 12\\\\[/tex]
The distance between the two points is about 12 units.
You could also use the pythagorean theorem as an alternative method.
