Answer:
122ft
Step-by-step explanation:
(Note that this is just a logical guess, I do not remember learning how to do this)
We are given the length of the pole and the length of the guy wire after the pole. This gives us a right angle triangle where we know two of the sides. We can the other two sides into the Pythagorean theorem to solve for the diagonal side
recall:
[tex]{a}^{2} + {b}^{2} = {c}^{2} [/tex]
plugged in 12ft and 2ft we get:
[tex] {(12)}^{2} + {(2)}^{2} = 148[/tex]
to solve for the diagonal side we take the square root of 148
[tex] \sqrt{148} = 12.17[/tex]
so now we know that 12.17 ft of wire is equivalent to 2 feet on the ground.
[tex] \frac{12.17ft \: wire}{2 \: ft \: ground} [/tex]
We have a total of 20 feet, so we multiply this proportion by 20:
[tex] \frac{12.17}{2} \times 20 = 121.7[/tex]
we are asked to give to the nearest foot so we round up to 122ft
