Answer:
W = P * t work = work/time * time
t = W / P time required
t = 2000 kg * 9.8 m/s2 * 28 m / P = 549,000 J / 13000 J/s
t = 42.2 sec
Note: 1 kW = 1000 J/sec
Time required for an elevator to lift a 2000 kg load up 28 m from the ground level, if the motor can produce 13 kW of electric power will be 42.22 seconds .
The time rate of doing work or delivering energy is called Electric Power
electric Power can be calculates by
electric Power = Work done / time
Given :
mass (m) = 2000 kg
height (h) = 28m
electric power (P) = 13 kW = 13 * 10^3
acceleration due to gravity (g) = 9.8 m/s^2
Since , the load has been taken to a certain height , hence work must be done and that work done is stored in the form of Potential Energy
Work done = m* g * h
= 2000 * 9.8 * 28
13000 = 2000 * 9.8 * 28 / time
Time = 2000 * 9.8 * 28 / 13000
Time = 42.22 seconds
Time required for an elevator to lift a 2000 kg load up 28 m from the ground level, if the motor can produce 13 kW of electric power will be 42.22 seconds .
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