There is a pair of parallel sides in the following shape.
what is the area of the shape? units^2

Answer:
A = 15 units²
Step-by-step explanation:
The figure has 1 pair of parallel sides and is therefore a trapezium.
The area (A) of a trapezium is calculated as
A = [tex]\frac{1}{2}[/tex] h (b₁ + b₂ )
where h is the perpendicular height between bases and b₁, b₂ are bases
here h = 3, b₁ = 3 , b₂ = 7 , then
A = [tex]\frac{1}{2}[/tex] × 3 × (3 + 7) = 1.5 × 10 = 15 units²
The area of the square is the square of one of its sides. The area of the plate is 15 units².
The area of the square is the square of one of its sides.
[tex]\text{Area of square} = a^2[/tex]
The area of a triangle is half the product of its base and height.
[tex]\rm\text{Area of Triangle} = \dfrac{1}{2} \times Base \times Height[/tex]
The shape of the plate can be divided into two parts a square of side 3 cm and a triangle with of base 4 cm and a height of 3 cm, therefore, the area of the plate is,
[tex]\text{The area of the shape} = \text{Area of the triangle} + \text{Area of the square}[/tex]
[tex]= (\dfrac{1}{2} \times 4 \times 3) + (3 \times 3)\\\\= 6 + 9\\\\=15\rm\ units^2[/tex]
Hence, the area of the plate is 15 units².
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