The solution to [tex]\sqrt{3x + 12} = 9[/tex] is x = 23 and it is not an extraneous solution
How to solve the equation?
The equation is given as:
[tex]\sqrt{3x + 12} = 9[/tex]
Take the square of both sides
3x + 12 = 81
Subtract 12 from both sides
3x = 69
Divide through by 3
x = 23
Substitute x = 23 in [tex]\sqrt{3x + 12} = 9[/tex]
[tex]\sqrt{3 * 23 + 12} = 9[/tex]
Evaluate the sum and product
[tex]\sqrt{81} = 9[/tex]
The above equation is true
Hence, the solution to [tex]\sqrt{3x + 12} = 9[/tex] is x = 23 and it is not an extraneous solution
Read more about extraneous solution at:
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