Respuesta :
Apply the maximum condition,
[tex]H'(t)=0\Rightarrow t=v/32[/tex]
Find the height at this time,
[tex]H(v/32)=\frac{v^2}{64}+s[/tex]
[tex]H'(t)=0\Rightarrow t=v/32[/tex]
Find the height at this time,
[tex]H(v/32)=\frac{v^2}{64}+s[/tex]