Answer:
Angular frequency, [tex]\omega=6.52\ rad/s[/tex]
Explanation:
Given that,
Amplitude of simple harmonic motion, A = 2.3 m
Maximum velocity of the object, [tex]v_{max}=15\ m/s[/tex]
To find,
The object's angular frequency.
Solution,
The equation of the displacement of particle is given by :
[tex]y=A\ cos(\omega t)[/tex]
On differentiating above equation, we get the expression for maximum velocity as :
[tex]v_{max}=A\times \omega[/tex]
[tex]\omega=\dfrac{v_{max}}{A}[/tex]
[tex]\omega=\dfrac{15\ m/s}{2.3\ m}[/tex]
[tex]\omega=6.52\ rad/s[/tex]
So, the angular frequency of the object is 6.52 rad/s.
