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Lesson 8: Systems of Equations and Inequalities Unit Test CE 2015
Algebra 1 Unit 7: Systems of Equations and Inequalities

Lesson 8 Systems of Equations and Inequalities Unit Test CE 2015 Algebra 1 Unit 7 Systems of Equations and Inequalities class=
Lesson 8 Systems of Equations and Inequalities Unit Test CE 2015 Algebra 1 Unit 7 Systems of Equations and Inequalities class=
Lesson 8 Systems of Equations and Inequalities Unit Test CE 2015 Algebra 1 Unit 7 Systems of Equations and Inequalities class=
Lesson 8 Systems of Equations and Inequalities Unit Test CE 2015 Algebra 1 Unit 7 Systems of Equations and Inequalities class=

Respuesta :

Answer:

We are asked to find which graph represents the solution of the given system of equations:

[tex]y=-x+2------------(1)[/tex]

and [tex]y=3x-1-------------(2)[/tex]

We find the intersection point of the two equations by solving these system of equations using elimination method as:

subtract equation (2) from equation (1) to obtain:

[tex]0=-4x+3[/tex]

[tex]3=4x[/tex]

[tex]x=\dfrac{3}{4}=0.75[/tex]

Also putting this value of x in equation (1) we get:

[tex]y=-\dfrac{3}{4}+2\\\\y=\dfrac{-3+4\times 2}{4}\\\\y=\dfrac{-3+8}{4}\\\\y=\dfrac{5}{4}=1.25[/tex]

Hence, the intersection point is:  (0.75,1.25).

Hence the graph that represents the solution of the system of given linear equations is attached to the answer.

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