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Three consecutive integers can be represented by the variable n, n+1 and n+2. If the sum of three consecutive integers is 57, what are the integers? I am confused with what it is asking.

Respuesta :

LammettHash
You have some unknown integer [tex]n[/tex], and you know that adding this and the next two integers, [tex]n+1[/tex] and [tex]n+2[/tex], gives a total of 57.

This means

[tex]n+(n+1)+(n+2)=57[/tex]

The task is to find all three unknown integers. Notice that if you know the value of [tex]n[/tex], then you pretty much know the value of the other three integers.

To find [tex]n[/tex], solve the equation above:

[tex]n+(n+1)+(n+2)=3n+3=57\implies 3n=54\implies n=\dfrac{54}3=18[/tex]

So if 18 is the first integer, then others must be 19 and 20.
ParadoxThinker11
You have to make the equation n+(n+1)+(n+2)=57.
So, 
n+(n+1)+(n+2)=57
3n+3=57
     -3  -3
3n=54
Divide 3 on both sides
n= 18

Answer:
n= 18
n+1= 19
n+2=20

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