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A 0.100-kilogram apple hangs in a tree 1.50 meters above the ground. Ignoring frictional effects, the total mechanical energy of the apple is _____.

0.00 J
less than 1.47 J but more than 0.00 J
exactly 1.47 J
more than 1.47 J

Respuesta :

mgh (.1*9.8*1.5
it would be exactly 1.47

Answer: The total mechanical energy stored in an apple is 1.47 Joules

Explanation:

Mass of the apple = 0.100 kg

Height at which apple is hanging = 1.50 m

Force on the apple = [tex]Mass \times g[/tex]

Velocity of the apple = 0 m/s

g = acceleration due gravity

Mechanical energy = Potential energy + Kinetic energy

= [tex]mass\times g\times height[/tex] + [tex]\frac{1}{2}mass\times (velocity)^2[/tex]

[tex]=0.100 kg\times 9.8 m/s^2\times 1.50 m+\frac{1}{2}\times 0.100 kg\times (0 m/s)^2=1.47 Joules[/tex]

The total mechanical energy stored in an apple is 1.47 Joules